题目:输入某年某月某日,判断这一天是这一年的第几天?
程序分析:以3月5日为例,应该先把前两个月的加起来,然后再加上5天即本年的第几天,特殊情况,闰年且输入月份大于2时需考虑多加一天:
程序源代码:
#!/usr/bin/python3 year = int(input('year:\n')) month = int(input('month:\n')) day = int(input('day:\n')) months = (0,31,59,90,120,151,181,212,243,273,304,334) if 0 < month <= 12: sum = months[month - 1] else: print ('data error') sum += day leap = 0 if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)): leap = 1 if (leap == 1) and (month > 2): sum += 1 print ('it is the %dth day.' % sum)
以上实例输出结果为:
year: 2015 month: 6 day: 7 it is the 158th day.
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